Find the correct result . Remember the maths is exact 👌
1+4=5
2+5=12
3+6=21
5+8=____.
Find the correct result . Remember the maths is exact 👌
1+4=5
2+5=12
3+6=21
5+8=____.
45
45
45
High school maths
45
45
getready wrote:High school maths
@bobby_123
Are you trying for fun with this reasoning que.
DD has many member to solve complex problem, so Post something challenging
Dev-m wrote:@bobby_123
Are you trying for fun with this reasoning que.DD has many member to solve complex problem, so Post something challenging
Ok .. wait for a minute
Mere hisaab se to 34 bhi ho sakta hai…
vijkap201 wrote:Mere hisaab se to 34 hota hai…
That was my answer in 8th standard. My school used to have some kind of NTSE preparation tests at school level. The coach always used to insist that questions might look simple but they are not and most of the questions demand out of box thinking.
Whoever answered that question had the answer as 45, but mine 34. My first solution to the problem was 45 too and I thought why would they ask this question if it was so obvious. I went to out of the box thinking mode and came at the conclusion that the obvious answer was a trap (out of the box thinking was to add everything).
He had picked out my paper and asked me to come to the board to explain it. I did and after that he stopped insisting too much on out of box thinking
PS- I didn’t take NTSE exams in 10th because our school trained us for 2 years but in 10th our Principal insisted that it would be a bad idea to do anything else but 10th exam.
rsai01 wrote:That was my answer in 8th standard. My school used to have some kind of NTSE preparation tests at school level. The coach always used to insist that questions might look simple but they are not and most of the questions demand out of box thinking.
Whoever answered that question had the answer as 45, but mine 34. My first solution to the problem was 45 too and I thought why would they ask this question if it was so obvious. I went to out of the box thinking mode and came at the conclusion that the obvious answer was a trap (out of the box thinking was to add everything).
He had picked out my paper and asked me to come to the board to explain it. I did and after that he stopped insisting too much on out of box thinking
PS- I didn’t take NTSE exams in 10th because our school trained us for 2 years but in 10th our Principal insisted that it would be a bad idea to do anything else but 10th exam.
Aapka final answer kya hai???
1+4 = 5
we have to find the correct result
Dev-m wrote:@bobby_123
Are you trying for fun with this reasoning que.DD has many member to solve complex problem, so Post something challenging
Read question once again
vijkap201 wrote:First series is crystal clear… Problem starts with second onwards…
That is what, you can’t make own rules even though it seems logical. From the second line on you can’t assume that the value of second line addition has to be added to answer from first, because you didn’t do anything like that to the first line to derive that answer. First line holds the key to the logic of this question.
rsai01 wrote:I can’t be wrong for the second after the entire class laughed at my out of box thinking of 34. My coach had told that I can’t be making up my own random rules even though it seems logical.
I will keep it simple at 45
In an excel sheet, cumulative total is found this way… Ain’t it???
45 bachcho wale question mat puch…thoda level bdha apna hutiye
Found this on stackexchange..incase if anyone is wondering about the possible outcomes
1 + 4 = 5
2 + 5 = 12
3 + 6 = 21
5 + 8 = ?
1 + 4 = 5
2 + 5 = 2 + 2(5) = 12
3 + 6 = 3 + 3(6) = 21
5 + 8 = 5 + 5(8) = 45
ALGORITHM: A + A(B) = C
ANSWER = 45
1 + 4 = 1 + 4 + (0) = 5
2 + 5 = 2 + 5 + (5) = 12
3 + 6 = 3 + 6 + (12) = 21
5 + 8 = 5 + 8 + (21) = 34
ALGORITHM: A + B + C’ = C, where C’ is the previous answer
ANS = 34
1 + 4 = 5 = 5
2 + 5 = (5 + 2) + (5) = 12
3 + 6 = (7 + 2) + (12) = 21
5 + 8 = (9 + 2) + (21) = 32
ALGORITHM: for {X=5, C = X + C’ , X = X+2 };, where C’ is the previous answer. A and B not used in equation,
ANS = 32
1 + 4 = 5
2 + 5 = 7 (base 5) =12
3 + 6 = 9 (base 4) = 21
5 + 8 = 13 (base 3) = 111
ALGORITHM: for {X=6, C = (A + B)^(10 → X), X -1} (First answer in Base6, then Base 5, then 4, etc…)
ANS = 111
1 + 4 = 5
2 + 5 = 7 (base 5) =12
3 + 6 = 9 (base 4) = 21
4 + 7 = 11 (base 3) = 102
5 + 8 = 13 (base 2) (aka binary) = 1101
ALGORITHM: for {X=6, C = (A + B)^(10 → X), X -1} (First answer in Base6, then
Base 5, then 4, etc…including “missing” numbers
ANS = 1101
Hats off… I could think of first two solutions..
Hats off… I could think of first two solutions..