Find the correct result . Remember the maths is exact
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45
45
High school maths
Asking reasoning question and saying maths problem!
45
45
Mere hisaab se to 34 bhi ho sakta hai… 
That was my answer in 8th standard. My school used to have some kind of NTSE preparation tests at school level. The coach always used to insist that questions might look simple but they are not and most of the questions demand out of box thinking.
Whoever answered that question had the answer as 45, but mine 34. My first solution to the problem was 45 too and I thought why would they ask this question if it was so obvious. I went to out of the box thinking mode and came at the conclusion that the obvious answer was a trap (out of the box thinking was to add everything).
He had picked out my paper and asked me to come to the board to explain it. I did and after that he stopped insisting too much on out of box thinking
PS- I didn’t take NTSE exams in 10th because our school trained us for 2 years but in 10th our Principal insisted that it would be a bad idea to do anything else but 10th exam.
1+4 = 5
we have to find the correct result
First series is crystal clear… Problem starts with second onwards… 
45 bachcho wale question mat puch…thoda level bdha apna hutiye
Found this on stackexchange..incase if anyone is wondering about the possible outcomes
1 + 4 = 5
2 + 5 = 12
3 + 6 = 21
5 + 8 = ?
1 + 4 = 5
2 + 5 = 2 + 2(5) = 12
3 + 6 = 3 + 3(6) = 21
5 + 8 = 5 + 5(8) = 45
ALGORITHM: A + A(B) = C
ANSWER = 45
1 + 4 = 1 + 4 + (0) = 5
2 + 5 = 2 + 5 + (5) = 12
3 + 6 = 3 + 6 + (12) = 21
5 + 8 = 5 + 8 + (21) = 34
ALGORITHM: A + B + C’ = C, where C’ is the previous answer
ANS = 34
1 + 4 = 5 = 5
2 + 5 = (5 + 2) + (5) = 12
3 + 6 = (7 + 2) + (12) = 21
5 + 8 = (9 + 2) + (21) = 32
ALGORITHM: for {X=5, C = X + C’ , X = X+2 };, where C’ is the previous answer. A and B not used in equation,
ANS = 32
1 + 4 = 5
2 + 5 = 7 (base 5) =12
3 + 6 = 9 (base 4) = 21
5 + 8 = 13 (base 3) = 111
ALGORITHM: for {X=6, C = (A + B)^(10 → X), X -1} (First answer in Base6, then Base 5, then 4, etc…)
ANS = 111
1 + 4 = 5
2 + 5 = 7 (base 5) =12
3 + 6 = 9 (base 4) = 21
4 + 7 = 11 (base 3) = 102
5 + 8 = 13 (base 2) (aka binary) = 1101
ALGORITHM: for {X=6, C = (A + B)^(10 → X), X -1} (First answer in Base6, then
Base 5, then 4, etc…including “missing” numbers
ANS = 1101
Another solution.
X² + Y + [3 * (X – 1)] = Z
Hats off… I could think of first two solutions..
Hats off… I could think of first two solutions..
Don’t use images na
Reverse google search is enough to get the answer 
45
This is how to solve mathematically. 
In simple terms
Acc to exact maths it is 13
. . . .
18
13
97
45
All correct
25 @balu44
Ans is 43
This is the correct solution
1+4=5
Drop the result to down 5+2+5=12
12+3+6=21
21+5+8=34
Hence 34 will be answer
Can anyone solve this question from Missing series.
0,4,18 48, ? 180
What will come in the question mark ?
100% guarantee no one can solve!
Missing no : 100?
45?
49
$0.05
The correct result is 1+4=5
45